Sulfur Dioxide And Oxygen Reaction
Question Sulphur dioxide and oxygen react according to the equation :- two S O ii ( g ) + O two ( grand ) → ii S O 3 ( g ) .If 50.0 1000 of S O 2 (g) is added to a flask resulting in a pressure level of 0.750 atm.What volition exist the total pressure in the flask when a stochiometric amount of oxygen is added?What is the pressure level afterwards the completion of reaction and before the beginning of the reaction (with O 2 simply added)? Before reaction = ane.125 atm , Subsequently reaction = 0.725 atm No worries! We've got your back. Try BYJU'Due south gratuitous classes today! Earlier reaction = 2.50 atm , Subsequently reaction = 1.000 atm No worries! We've got your back. Endeavor BYJU'Due south gratuitous classes today! Before reaction = one.125 atm , Subsequently reaction = 0.750 atm Right on! Give the BNAT exam to become a 100% scholarship for BYJUS courses Before reaction = 2.50 atm , After reaction = one.125 atm No worries! Nosotros've got your back. Attempt BYJU'S gratuitous classes today!
Open in App Solution The right selection is C Earlier reaction = i.125 atm , After reaction = 0.750 atm Since the stochiometric ratio of the Due south O 2 a n d South O iii are the same,the pressure in the flask after the reaction when the only substance in the flask is S O 3 will be the same as the pressure in flask when there is merely S O 2 is 0.750 atm. From the equation , stochiometric ratio of the O 2 is half of that of South O 2 .So afterwards oxygen is added, the total pressure in the flask volition exist 0.750 + 0.750 ii = 1.125 a t chiliad .So,the pressure will be ane.125 atm when the O two is only added. 
Sulfur Dioxide And Oxygen Reaction,
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