Sodium Hydroxide Density In G/ml

OVERVIEW

• A l% (west/w) concentrated Sodium hydroxide solution is a clear colorless liquid. It can be purchased from many suppliers.
• A l% (w/west) sodium hydroxide solution means that in that location is 50 g of NaOH per 100 g of solution.
  
• The density of 50% (w/westward) Sodium hydroxide solution is 1.515 g/ml at 25°C which ways that the weight of the i ml of Sodium hydroxide solution is 1.515 g at 25°C.
• Molarity refers to the number of moles of the solute nowadays in ane liter of solution.
• In unproblematic words, 1 mole is equal to the diminutive weight of the substance. For case, 1 mole of Sodium hydroxide is equal to 40.00 grams of Sodium hydroxide (NaOH, molecular weight = 40.00).
• To calculate the molarity, one must showtime calculate how much Sodium hydroxide is nowadays in 1 L of 50% Sodium hydroxide solution. Once we know the corporeality of sodium hydroxide present in 1 L solution, nosotros can calculate the molarity of the solution by dividing the NaOH amount past the molecular weight.

Calculation procedure:

Known values
Molar mass of Sodium Hydroxide	xl.00 g/mole
Concentration of Sodium Hydroxide solution	50% (% past mass, w/w)
Density of fifty% (due west/w) Sodium Hydroxide solution	ane.515 g/ml

Pace ane: Calculate the volume of 100 grams of Sodium Hydroxide solution.
Formula:

Density = $\frac{Weight}{Volume}$

OR

Volume = $\frac{\mathrm{Weight}}{\mathrm{Density}}$

The volume of 100 grand of Sodium hydroxide solution: $\frac{100}{\mathrm{one}.515}$ = 66.0066 ml

Note: fifty% (w/west) Sodium Hydroxide ways that 100 1000 of solution contains 50 1000 of Sodium Hydroxide.

The volume of 100 m of Sodium hydroxide solution is 66.0066 ml which ways 50 g of NaOH is nowadays in 66.0066 ml of  Sodium hydroxide solution.

Stride two: Calculate how many grams of NaOH is present in 1000 ml of Sodium hydroxide solution.
66.0066 ml of Sodium Hydroxide solution contains   = l grams of NaOH
1 ml of Sodium hydroxide solution will comprise      = $\frac{50}{66.0066}$ grams of NaOH

1000 ml of Sodium hydroxide solution will incorporate = $\frac{\mathrm{one\; thousand}\mathrm{ten}50}{66.0066}$ = 757.50 grams of NaOH

1000 ml of Sodium hydroxide solution will contain 757.50 grams of NaOH.

Step iii: Summate the number of moles of NaOH nowadays in 757.fifty grams of NaOH.
xl g of NaOH is equal to ane mole.

1 one thousand of NaOH will be equal to $\frac{\mathrm{one}}{40}$ moles.

$757.\mathrm{fifty}gofNaOHwi\mathrm{50}lb\mathrm{due\; east}\mathrm{eastward}qualto=\frac{757.50x1}{40}=\mathrm{eighteen}.9375mo\mathrm{50}es$

Therefore, we can say that 1 liter of sodium hydroxide solution contains eighteen.9375 moles or in other words molarity of l% (w/w) Sodium Hydroxide is equal to eighteen.9375 1000.

Calculator – Calculate the molarity of concentrated Sodium Hydroxide (NaOH)
Use Reckoner to calculate the molarity of concentrated Sodium Hydroxide (NaOH) when concentration is given in % by mass (w/due west)

Sodium Hydroxide (NaOH) Molecular weight: twoscore.00 yard/mole

Concentration of Sodium Hydroxide in % (wt/wt) : % (wt/wt)

(Change the % (wt/wt) concentration)

Density of glacial Sodium Hydroxide: thou/ml

(Change the density)

Molarity of Sodium Hydroxide: 18.938 Thousand

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Sodium Hydroxide Density In G/ml,

Source: https://www.laboratorynotes.com/molarity-of-50-percent-sodium-hydroxide-naoh/

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